Given the head of a linked list and an integer val, remove all the nodes of the linked list that has Node.val == val, and return the new head.
Example 1:
Input: head = [1,2,6,3,4,5,6], val = 6
Output: [1,2,3,4,5]
Example 2:
Input: head = [], val = 1
Output: []
Example 3:
Input: head = [7,7,7,7], val = 7
Output: []
Constraints:
The number of nodes in the list is in the range [0, 104].
1 <= Node.val <= 50
0 <= k <= 50
Solution:1
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26/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode removeElements(ListNode head, int val) {
while (head != null && head.val == val) {
head = head.next;
}
ListNode tmp = head;
while (tmp != null && tmp.next != null) {
if (tmp.next.val == val) {
tmp.next = tmp.next.next;
} else {
tmp = tmp.next;
}
}
return head;
}
}